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Trigonometry : Solving Word Problems with Trigonometry

Study concepts, example questions & explanations for trigonometry, all trigonometry resources, example questions, example question #1 : solving word problems with trigonometry.

word problems trigonometry with solutions

You can draw the following right triangle using the information given by the question:

1

Since you want to find the height of the platform, you will need to use tangent.

word problems trigonometry with solutions

You can draw the following right triangle from the information given by the question.

2

In order to find the height of the flagpole, you will need to use tangent.

word problems trigonometry with solutions

You can draw the following right triangle from the information given in the question:

3

In order to find out how far up the ladder goes, you will need to use sine.

word problems trigonometry with solutions

In right triangle ABC, where angle A measures 90 degrees, side AB measures 15 and side AC measures 36, what is the length of side BC?

word problems trigonometry with solutions

This triangle cannot exist.

word problems trigonometry with solutions

Example Question #5 : Solving Word Problems With Trigonometry

A support wire is anchored 10 meters up from the base of a flagpole, and the wire makes a 25 o angle with the ground. How long is the wire, w? Round your answer to two decimal places.

23.81 meters

word problems trigonometry with solutions

28.31 meters

21.83 meters

To make sense of the problem, start by drawing a diagram. Label the angle of elevation as 25 o , the height between the ground and where the wire hits the flagpole as 10 meters, and our unknown, the length of the wire, as w. 

Screen shot 2020 07 13 at 12.54.08 pm

Now, we just need to solve for w using the information given in the diagram. We need to ask ourselves which parts of a triangle 10 and w are relative to our known angle of 25 o . 10 is opposite this angle, and w is the hypotenuse. Now, ask yourself which trig function(s) relate opposite and hypotenuse. There are two correct options: sine and cosecant. Using sine is probably the most common, but both options are detailed below.

We know that sine of a given angle is equal to the opposite divided by the hypotenuse, and cosecant of an angle is equal to the hypotenuse divided by the opposite (just the reciprocal of the sine function). Therefore:

word problems trigonometry with solutions

To solve this problem instead using the cosecant function, we would get:

word problems trigonometry with solutions

The reason that we got 23.7 here and 23.81 above is due to differences in rounding in the middle of the problem. 

word problems trigonometry with solutions

Example Question #6 : Solving Word Problems With Trigonometry

When the sun is 22 o above the horizon, how long is the shadow cast by a building that is 60 meters high?

To solve this problem, first set up a diagram that shows all of the info given in the problem. 

Screen shot 2020 07 13 at 1.38.59 pm

Next, we need to interpret which side length corresponds to the shadow of the building, which is what the problem is asking us to find. Is it the hypotenuse, or the base of the triangle? Think about when you look at a shadow. When you see a shadow, you are seeing it on something else, like the ground, the sidewalk, or another object. We see the shadow on the ground, which corresponds to the base of our triangle, so that is what we'll be solving for. We'll call this base b.

word problems trigonometry with solutions

Therefore the shadow cast by the building is 150 meters long.

If you got one of the incorrect answers, you may have used sine or cosine instead of tangent, or you may have used the tangent function but inverted the fraction (adjacent over opposite instead of opposite over adjacent.)

Example Question #7 : Solving Word Problems With Trigonometry

From the top of a lighthouse that sits 105 meters above the sea, the angle of depression of a boat is 19 o . How far from the boat is the top of the lighthouse?

423.18 meters

318.18 meters

36.15 meters

110.53 meters

To solve this problem, we need to create a diagram, but in order to create that diagram, we need to understand the vocabulary that is being used in this question. The following diagram clarifies the difference between an angle of depression (an angle that looks downward; relevant to our problem) and the angle of elevation (an angle that looks upward; relevant to other problems, but not this specific one.) Imagine that the top of the blue altitude line is the top of the lighthouse, the green line labelled GroundHorizon is sea level, and point B is where the boat is.

Screen shot 2020 07 13 at 3.07.05 pm

Merging together the given info and this diagram, we know that the angle of depression is 19 o  and and the altitude (blue line) is 105 meters. While the blue line is drawn on the left hand side in the diagram, we can assume is it is the same as the right hand side. Next, we need to think of the trig function that relates the given angle, the given side, and the side we want to solve for. The altitude or blue line is opposite the known angle, and we want to find the distance between the boat (point B) and the top of the lighthouse. That means that we want to determine the length of the hypotenuse, or red line labelled SlantRange. The sine function relates opposite and hypotenuse, so we'll use that here. We get:

word problems trigonometry with solutions

Example Question #8 : Solving Word Problems With Trigonometry

Angelina just got a new car, and she wants to ride it to the top of a mountain and visit a lookout point. If she drives 4000 meters along a road that is inclined 22 o to the horizontal, how high above her starting point is she when she arrives at the lookout?

9.37 meters

1480 meters

3708.74 meters

10677.87 meters

1616.1 meters

As with other trig problems, begin with a sketch of a diagram of the given and sought after information.

Screen shot 2020 07 13 at 5.37.06 pm

Angelina and her car start at the bottom left of the diagram. The road she is driving on is the hypotenuse of our triangle, and the angle of the road relative to flat ground is 22 o . Because we want to find the change in height (also called elevation), we want to determine the difference between her ending and starting heights, which is labelled x in the diagram. Next, consider which trig function relates together an angle and the sides opposite and hypotenuse relative to it; the correct one is sine. Then, set up:

word problems trigonometry with solutions

Therefore the change in height between Angelina's starting and ending points is 1480 meters. 

Example Question #9 : Solving Word Problems With Trigonometry

Two buildings with flat roofs are 50 feet apart. The shorter building is 40 feet tall. From the roof of the shorter building, the angle of elevation to the edge of the taller building is 48 o . How high is the taller building?

To solve this problem, let's start by drawing a diagram of the two buildings, the distance in between them, and the angle between the tops of the two buildings. Then, label in the given lengths and angle. 

Screen shot 2020 07 13 at 5.56.45 pm

Example Question #10 : Solving Word Problems With Trigonometry

Two buildings with flat roofs are 80 feet apart. The shorter building is 55 feet tall. From the roof of the shorter building, the angle of elevation to the edge of the taller building is 32 o . How high is the taller building?

Screen shot 2020 07 13 at 5.58.09 pm

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Trigonometry Word Problems

Contextual use of triangle properties, ratios, theorems, and laws..

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Home > Math Worksheets > Word Problems > Trigonometry

These types of problems focus on the lengths of sides and angles within a triangle. After all that is what trigonometry is all about. Start to approach these problems by focusing on understanding the figures that are involved and model this by drawing diagrams. On the diagram highlight all the information that we know about each stage of the diagram. Make sure that if a unit of measure is attached to that information that you show that as well. We then start to analyze the system and identify if Pythagorean Theorem comes into play or if we can apply various trigonometric functions to determine the angle of elevation or depression.

In these worksheets, your students will solve word problems involving trigonometry. Diagrams are included to accompany some problems. These are moderately complex problems and a sound understanding of trigonometry is required in order for students to be successful with these worksheets. There are six worksheets in this set. This set of worksheets contains lessons, step-by-step solutions to sample problems, and both simple and more complex problems. It also includes ample worksheets for students to practice independently. Students may require extra paper on which to do their calculations. Most worksheets contain between eight and eleven problems. When finished with this set of worksheets, students will be able to solve word problems that involve trigonometry. These worksheets explain how to solve word problems by using trigonometry. Sample problems are solved and practice problems are provided.

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Trigonometry word problems worksheets, click the buttons to print each worksheet and answer key., trigonometric word problem lesson.

This worksheet explains how to solve word problems by using trigonometry. A sample problem is solved, and two practice problems are provided.

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You are stationed at a radar base and you observe an unidentified plane at an altitude h = 2000 m flying towards your radar base at an angle of elevation = 30o. After exactly one minute, your radar sweep reveals that the plane is now at an angle of elevation = 60o maintaining the same altitude. What is the speed (in m/s) of the plane?

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A fisherman drops a boat anchor and pays out 93 meter of anchor rope. The rope makes an angle of depression of 59.5 degrees with the horizontal. Assuming a level bottom, how deep in the water?

Review and Practice

What is the measure of the diagonal of the rectangle ABHG ?

A tree in a back yard is to be cut down. The base of the tree from the house is 23 meters away, and the angle of elevation from the house to the top of the tree is 45.5 degrees. Could the tree hit the house when it is cut down?

An aerial 30 meter tail is to be supported by 2 guy wires each 50 meter from its base. How long will each guy wire be?

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4.1.7: Trigonometry Word Problems

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Contextual use of triangle properties, ratios, theorems, and laws.

Angle of Depression and Angle of Elevation

One application of the trigonometric ratios is to find lengths that you cannot measure. Very frequently, angles of depression and elevation are used in these types of problems.

Angle of Depression: The angle measured down from the horizon or a horizontal line.

f-d_11bf18af5666b61e4d6724866493268beed0ea77a493be4a55d034cd+IMAGE_TINY+IMAGE_TINY.png

Angle of Elevation: The angle measured up from the horizon or a horizontal line.

f-d_534e33faaea24b855732a19161f007b90372910fcfd3947bca6a928a+IMAGE_TINY+IMAGE_TINY.png

What if you placed a ladder 10 feet from a haymow whose floor is 20 feet from the ground? How tall would the ladder need to be to reach the haymow's floor if it forms a \(30^{\circ}\) angle with the ground?

Example \(\PageIndex{1}\)

A math student is standing 25 feet from the base of the Washington Monument. The angle of elevation from her horizontal line of sight is \(87.4^{\circ}\). If her “eye height” is 5 ft, how tall is the monument?

f-d_2af93ad05e8721329abfdb1b17a45f1714635781d9c6799317db1e95+IMAGE_TINY+IMAGE_TINY.png

We can find the height of the monument by using the tangent ratio.

\(\begin{aligned} \tan 87.4^{\circ} &=\dfrac{h}{25} \\ h&=25\cdot \tan 87.4^{\circ}=550.54 \end{aligned}\)

Adding 5 ft, the total height of the Washington Monument is 555.54 ft.

Example \(\PageIndex{2}\)

A 25 foot tall flagpole casts a 42 foot shadow. What is the angle that the sun hits the flagpole?

f-d_e09766cbe751238b20d807567c6a6d1bea215da9796837602f15f275+IMAGE_TINY+IMAGE_TINY.png

Draw a picture. The angle that the sun hits the flagpole is \(x^{\circ}\). We need to use the inverse tangent ratio.

\(\begin{aligned} \tan x &=\dfrac{42}{25} \\ \tan^{−1} \dfrac{42}{25}&\approx 59.2^{\circ}=x \end{aligned}\)

Example \(\PageIndex{3}\)

Elise is standing on top of a 50 foot building and sees her friend, Molly. If Molly is 30 feet away from the base of the building, what is the angle of depression from Elise to Molly? Elise’s eye height is 4.5 feet.

Because of parallel lines, the angle of depression is equal to the angle at Molly, or \(x^{\circ}\). We can use the inverse tangent ratio.

\(\tan^{−1} \left(\dfrac{54.5}{30}\right)=61.2^{\circ}=x\)

f-d_806dd2da7f27417fc6f083793250209e5f83f9e03f681da8bf8972e7+IMAGE_TINY+IMAGE_TINY.png

Example \(\PageIndex{4}\)

Mark is flying a kite and realizes that 300 feet of string are out. The angle of the string with the ground is \(42.5^{\circ}\). How high is Mark's kite above the ground?

It might help to draw a picture. Then write and solve a trig equation.

\(\begin{aligned} \sin 42.5^{\circ} &=\dfrac{x}{300}\\ 300\cdot \sin 42.5^{\circ} &=x \\ x&\approx 202.7\end{aligned}\)

The kite is about 202.7 feet off of the ground.

Example \(\PageIndex{5}\)

A 20 foot ladder rests against a wall. The base of the ladder is 7 feet from the wall. What angle does the ladder make with the ground?

It might help to draw a picture.

\(\begin{aligned} \cos x &=\dfrac{7}{20}\\ x&=\cos ^{−1}\dfrac{7}{20}\\ x&\approx 69.5^{\circ}\end{aligned}\)

f-d_5c0e35e3123f7876fa7e7a67793341871e9c0a5d2c77972f222bc9dd+IMAGE_TINY+IMAGE_TINY.png

Use what you know about right triangles to solve for the missing angle. If needed, draw a picture. Round all answers to the nearest tenth of a degree.

  • A 75 foot building casts an 82 foot shadow. What is the angle that the sun hits the building?
  • Over 2 miles (horizontal), a road rises 300 feet (vertical). What is the angle of elevation?
  • A boat is sailing and spots a shipwreck 650 feet below the water. A diver jumps from the boat and swims 935 feet to reach the wreck. What is the angle of depression from the boat to the shipwreck?
  • Standing 100 feet from the base of a building, Sam measures the angle to the top of the building from his eye height to be \(50^{\circ}\). If his eyes are 6 feet above the ground, how tall is the building?
  • Over 4 miles (horizontal), a road rises 200 feet (vertical). What is the angle of elevation?
  • A 90 foot building casts an 110 foot shadow. What is the angle that the sun hits the building?
  • Luke is flying a kite and realizes that 400 feet of string are out. The angle of the string with the ground is \(50^{\circ}\). How high is Luke's kite above the ground?
  • An 18 foot ladder rests against a wall. The base of the ladder is 10 feet from the wall. What angle does the ladder make with the ground?

Review (Answers)

To see the Review answers, open this PDF file and look for section 8.9.

Term Definition
The angle of depression is the angle formed by a horizontal line and the line of sight down to an object when the image of an object is located beneath the horizontal line.
The angle of elevation is the angle formed by a horizontal line and the line of sight up to an object when the image of an object is located above the horizontal line.
ASA, angle-side-angle, refers to two known angles in a triangle with one known side between the known angles.
The law of cosines is a rule relating the sides of a triangle to the cosine of one of its angles. The law of cosines states that c2=a2+b2−2abcosC, where C is the angle across from side c.
The law of sines is a rule applied to triangles stating that the ratio of the sine of an angle to the side opposite that angle is equal to the ratio of the sine of another angle in the triangle to the side opposite that angle.
The tangent of an angle in a right triangle is a value found by dividing the length of the side opposite the given angle by the length of the side adjacent to the given angle.
Ratios that help us to understand the relationships between sides and angles of right triangles.

Additional Resources

Interactive element.

Video: Trigonometry Word Problems Principles - Basic

Activities: Trigonometry Word Problems Discussion Questions

Practice: Trigonometry Word Problems

Real World: Measuring Mountains

TRIGONOMETRY WORD PROBLEMS WITH SOLUTIONS

Problem 1 :

The angle of elevation of the top of the building at a distance of 50 m from its foot on a horizontal plane is found to be 60 °. Find the height of the building.

Draw a sketch.

word problems trigonometry with solutions

Here, AB represents height of the building, BC represents distance of the building from the point of observation.

In the right triangle ABC, the side which is opposite to the angle 60° is known as opposite side (AB), the side which is opposite to 90° is called hypotenuse side (AC) and the remaining side is called adjacent side (BC).

Now we need to find the length of the side AB.

tanθ = Opposite side/Adjacent side

tan60° = AB/BC

√3 x 50 = AB

Approximate value of √3 is 1.732

AB = 50 (1.732)

     AB = 86.6 m

So, the height of the building is 86.6 m.

Problem 2 : 

A ladder placed against a wall such that it reaches the top of the wall of height 6 m and the ladder is inclined at an angle of 60 ° . Find how far the ladder is from the foot of the wall.

word problems trigonometry with solutions

Here AB represents height of the wall, BC represents the distance between the wall and the foot of the ladder and AC represents the length of the ladder.

In the right triangle ABC, the side which is opposite to angle 60° is known as opposite side (AB), the side which is opposite to 90° is called hypotenuse side (AC) and remaining side is called adjacent side (BC).

Now, we need to find the distance between foot of the ladder and the wall. That is, we have to find the length of BC.

tanθ = opposite side/adjacent side

BC = (6/√3) x (√3/√3)

BC = (6√3)/3

Approximate value of √3 is 1.732.

BC = 2 (1.732)

BC = 3.464 m 

So,  the distance between foot of the ladder and the wall is 3.464 m.

Problem 3 :

A string of a kite is 100 meters long and t he inclination of the string  with the ground is  60°. Find the height of the kite, assuming that there is no slack in the string.

word problems trigonometry with solutions

Here AB represents height of kite from the ground, BC represents the distance of kite from the point of observation.

In the right triangle ABC the side which is opposite to angle 60° is known as opposite side (AB), the side which is opposite to 90° is called hypotenuse side (AC) and remaining side is called adjacent side (BC).

Now we need to find the height of the side AB.

sinθ = opposite side/hypotenuse side

sinθ = AB/AC

sin60° = AB/100

√3/2 = AB/100

(√3/2) x 100 = AB

AB = 50√3 m

So, the height of kite from the ground 50√3 m.

Problem 4 :

From the top of the tower 30 m height a man is observing the base of a tree at an angle of depression measuring 30 ° . Find the distance between the tree and the tower.

word problems trigonometry with solutions

Here AB represents height of the tower, BC represents the distance between foot of the tower and the foot of the tree.

Now we need to find the distance between foot of the tower and the foot of the tree (BC).

tan30° = AB/BC

1/√3 = 30/BC

BC = 30(1.732)

 BC = 51.96 m

So, the distance between the tree and the tower is 51.96 m.

Problem 5 :

A man wants to determine the height of a light house. He measured the angle at A and found that tan A = 3/4. What is the height of the light house if A is 40m from the base?

word problems trigonometry with solutions

Here BC represents height of the light house, AB represents the distance between the light house from the point of observation.

In the right triangle ABC the side which is opposite to the angle A is known as opposite side (BC), the side which is opposite to 90° is called hypotenuse side (AC) and remaining side is called adjacent side (AB).

Now we need to find the height of the light house (BC).

tanA = opposite side/adjacent side

tanA = BC/AB

Given : tanA = 3/4.

3/4 = BC/40

Multiply each side by 40.

So, the height of the light house is 30 m.

Problem 6 :

A ladder is leaning against a vertical wall makes an angle of 20° with the ground. The foot of the ladder is 3 m from the wall. Find the length of ladder.

word problems trigonometry with solutions

Here AB represents height of the wall, BC represents the distance of the wall from the foot of the ladder.

In the right triangle ABC, the side which is opposite to the angle 20° is known as opposite side (AB),the side which is opposite to 90° is called hypotenuse side (AC) and remaining side is called adjacent side (BC).

Now we need to find the length of the ladder (AC).

cosθ = adjacent side/hypotenuse side

Cosθ = BC/AC

Cos 20° = 3/AC

0.9397 = 3/AC

AC = 3/0.9396

So, the length of the ladder is about 3.193 m.

Problem 7 :

A kite is flying at a height of 65 m attached to a string. If the inclination of the string with the ground is 31°,  find the length of string.

word problems trigonometry with solutions

Here AB represents height of the kite. In the right triangle ABC the side which is opposite to angle 31° is known as opposite side (AB), the side which is opposite to 90° is called hypotenuse side (AC) and the remaining side is called adjacent side (BC).

Now we need to find the length of the string AC.

sin31° = AB/AC

0.5150 = 65/AC

AC = 65/0.5150

AC = 126.2 m

Hence, the length of the string is 126.2 m.

Problem 8 :

The length of a string between a kite and a point on the ground is 90 m. If the string makes an angle θ with the ground level such that tan θ = 15/8, how high will the kite be ?

word problems trigonometry with solutions

Here AB represents height of the balloon from the ground. In the right triangle ABC the side which is opposite to angle θ is known as opposite side (AB), the side which is opposite to 90° is called hypotenuse side (AC) and remaining side is called adjacent side (BC).

tanθ = 15/8 ----> cotθ = 8/15

cscθ = √(1+ cot 2 θ)

cscθ = √(1 + 64/225)

cscθ = √(225 + 64)/225

cscθ = √289/225

cscθ = 17/15 ----> sinθ = 15/17

But, sinθ = opposite side/hypotenuse side = AB/AC.

AB/AC = 15/17

AB/90 = 15/17

So, the height of the tower is 79.41 m.

Problem 9 :

An airplane is observed to be approaching a point that is at a distance of 12 km from the point of observation and makes an angle of elevation of 50°. Find the height of the airplane above the ground.

word problems trigonometry with solutions

Here AB represents height of the airplane from the ground. In the right triangle ABC the side which is opposite to angle 50° is known as opposite side (AB), the side which is opposite to 90° is called hypotenuse side (AC) and remaining side is called adjacent side (BC).

From the figure given above, AB stands for the height of the airplane above the ground.

sin50° = AB/AC

0.7660 = h/12

0.7660 x 12 = h

So, the height of the airplane above the ground is 9.192 km.

Problem 10 :

A balloon is connected to a meteorological station by a cable of length 200 m inclined at 60 °  angle with the ground. Find the  height of the balloon from the ground. (Imagine that there is no slack in the cable)

word problems trigonometry with solutions

Here AB represents height of the balloon from the ground. In the right triangle ABC the side which is opposite to angle 60° is known as opposite side (AB), the side which is opposite to 90° is called hypotenuse (AC) and the remaining side is called as adjacent side (BC).

From the figure given above, AB stands for the height of the balloon above the ground.

sin60° = AB/200

√3/2 = AB/200

AB = (√3/2) x 200

AB = 100(1.732)

AB = 173.2 m

So, the height of the balloon from the ground is 173.2 m.

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Webcomic #33  " Ye Olde Trig Homework " by Lance Friedman

In the comic, what is the height of the kite?  

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Trigonometric Functions WORD problems

Ferris wheel trigonometry word problem.

The Ferris wheel at Navy Pier has a diameter of 140 feet. It stands 10 feet off the ground. The wheel has 40 gondolas that seat six passengers each. It takes about 6 minutes for the Navi Pier Ferris wheel to complete one rotation.

Draw a diagram of the Navy Pier Ferris wheel and the boarding platform. Fill in the necessary information. Sketch the graph. Write a cosine equation for your curve. Write a sine equation for your curve.

Answer the following questions:

i. What is the circumference of the wheel?

ii. At what speed is the wheel traveling? Please answer in feet / second.

iii. If you begin your ride at the base of the wheel, what is the height after 1 minute? 4 minutes?

iv. At what approximate time(s) will you reach the following heights?

v. What is the length of the arc traveled by the Navy Pier Ferris wheel from the 4 o’clock to the 7 o’clock position?

Solution to this Trigonometric Function word practice  problem is provided in the video below!

Roller Coaster trigonometry problem

A portion of a roller coaster is to be built in the shape of a sinusoid. You have been hired to calculate the lengths of the horizontal and vertical timber supports to be used.

a. The high and low points on the track are separated by 50 meters horizontally and 30 meters vertically. The low point is 3 meters below the ground. Letting y be the number of meters the track is above the ground and x the number of meters horizontally from the high point, write an equation expressing y in terms of x .

b. How long is the vertical timber at the high point? At x = 4 m? At x = 32 m?

c. Where does the track first go below ground?

Solution to this Trigonometric Function example practice  problem is provided in the video below!

Steamboat trigonometry example word problem

Mark Twain sat on the deck of a river steamboat. As the paddlewheel turned, a point on the paddle blade moved in such a way that its distance, d , from the water’s surface was a sinusoidal function of time. When his stopwatch read 4 seconds, the point was at its highest, 16 feet above the water’s surface. The wheel’s diameter was 18 feet, and it completed a revolution every 10 seconds.

a. Sketch a graph of the sinusoid

b. Write the equation of the sinusoid

c. How far above the surface was the point when Mark’s stopwatch read:

i. 5 seconds

ii. 17 seconds

d. What is the first positive value of time at which the point was at the water’s surface? At that time, was it going into or coming out of the water? Explain.

Solution to this Trigonometric Function example word problem is provided in the video below!

Temperature trigonometry word problem

The max temperature in Buenos Aires is on January 15 and is 33 degrees Celsius. The minimum temperature is on July 16 (day 197) and is 9 degrees Celsius. (Assume the period is 365 days).

a) Sketch the temperature as a function of time

b) Find the equation for the temperature, T, as a function of time, t.

c) What is the temperature on Mother’s Day, May 10?

d) Give the dates during a one year period when the temperature is below 18 degrees Celsius.

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  • Trigonometry Word Problems

Trigonometry word problems involve applying the principles of trigonometric ratios —sine, cosine, and tangent—to solve real-world scenarios such as determining heights, distances, and angles . Mastery of these problems requires a thorough understanding of right-angle triangles and the Pythagorean theorem. By practising, students can enhance their problem-solving skills and effectively use trigonometry in practical situations.

Trigonometry Word Problems

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What is Trigonometry?

What are the main steps to solve trigonometry word problems?

What is the value of the height of a tree if it casts a shadow of 10 metres and the angle of elevation of the sun is 30 degrees?

How would you find the distance from the base of the ladder to the wall if the ladder is 5 metres long and the angle between the ladder and the ground is 60 degrees?

What is the height of a building if viewed from a distance of 50 metres with an angle of elevation of 45 degrees?

Given triangle ABC with sides a = 8, b = 6, and angle C = 60 degrees, how do you find side c?

What is one everyday application of trigonometry for measuring heights?

How can trigonometry be used in astronomy?

What is the law of cosines formula used in engineering?

What is the correct ratio for the sine function?

How do you find the height of a tree if you stand 30 metres away and the angle of elevation is 45 degrees?

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Introduction to Trigonometry Word Problems

Trigonometry word problems apply the principles of trigonometry to real-life scenarios. Understanding these problems helps you see the practical uses of mathematics, from measuring heights to navigating maps.

The Importance of Trigonometry Word Problems

Understanding trigonometry word problems allows you to apply trigonometric concepts to practical situations. This not only enhances your problem-solving skills but also shows how maths is used in various fields such as engineering, physics, and navigation.

Trigonometry: A branch of mathematics that studies relationships between side lengths and angles of triangles.

Key Trigonometric Functions

In trigonometry, three main functions are used to solve problems involving right-angled triangles:

  • Sine (sin): The ratio of the length of the opposite side to the hypotenuse.
  • Cosine (cos): The ratio of the length of the adjacent side to the hypotenuse.
  • Tangent (tan): The ratio of the length of the opposite side to the adjacent side.

Example: Given a right-angled triangle where the opposite side is 3 units , the adjacent side is 4 units, and the hypotenuse is 5 units:

  • sin(θ) = 3/5
  • cos(θ) = 4/5
  • tan(θ) = 3/4

Steps to Solving Trigonometry Word Problems

To tackle trigonometry word problems effectively, follow these steps:

  • Understand the problem: Read the problem statement carefully to determine what is being asked.
  • Identify the right triangle: Sketch the scenario and highlight the right-angled triangle.
  • Choose the correct function: Decide whether to use sine, cosine, or tangent based on the given information.
  • Set up the equation: Write the equation using the chosen trigonometric function and solve for the unknown.
  • Check your answer: Confirm if the solution is reasonable and correctly answers the problem.

Sometimes, trigonometry word problems may involve more complex scenarios, such as non-right triangles or 3D contexts. In such cases, you might need to use advanced trigonometric principles like the law of sines or the law of cosines. These laws generalise the basic trigonometric functions and can handle various triangle types.

Example Problem

Example: A tree casts a shadow of 10 metres, and the angle of elevation of the sun is 30 degrees. Find the height of the tree.Solution:

  • Let the height of the tree be h.
  • tan(30) = h / 10
  • Since tan(30) = 1/√3, then 1/√3 = h / 10.
  • h = 10 / √3 ≈ 5.77 metres.

Common Mistakes to Avoid

When solving trigonometry word problems, some common mistakes include:

  • Not identifying the right function: Ensure you choose the correct trigonometric function (sine, cosine, or tangent) based on the given information.
  • Forgetting to use the correct units : Always keep track of the units and convert them if necessary.
  • Not checking your work: Always recheck your calculations and ensure your answer makes sense in the context of the problem.
  • Not using a calculator properly: Ensure your calculator is set to the correct mode (degrees or radians ) based on the angle measures used in the problem.

To avoid mistakes, always double-check your chosen trigonometric function and ensure your units are consistent.

Trigonometry Word Problems Examples

Trigonometry word problems involve using trigonometric principles to solve practical problems. These problems can range from understanding heights and distances to complex angle calculations.

Simple Trigonometry Word Problems Examples

Simple trigonometry word problems often involve right-angled triangles and basic trigonometric functions like sine, cosine, and tangent. Let's take a look at an example.

Example: A ladder is leaning against a wall, forming a right-angled triangle with the ground. If the ladder is 5 metres long and the angle between the ladder and the ground is 60 degrees, find the distance from the base of the ladder to the wall.Solution:

  • Let the distance from the base of the ladder to the wall be x.
  • Using the cosine function, cos(60) = x / 5
  • Since cos(60) = 1/2, then 1/2 = x / 5.
  • So, x = 5 / 2 = 2.5 metres.

Always start by identifying what is given and what you need to find. This will help you choose the right trigonometric function.

Intermediate Trigonometry Word Problems Examples

Intermediate problems may require you to use multiple trigonometric functions and incorporate more complex geometric shapes. These problems will often involve finding unknown angles or distances.

Example: You are looking at the top of a building from a distance of 50 metres. If the angle of elevation is 45 degrees, find the height of the building.Solution:

  • Let the height of the building be h.
  • Using the tangent function, tan(45) = h / 50
  • Since tan(45) = 1, then 1 = h / 50.
  • So, h = 50 metres.

For more complex shapes, you might need to break the problem into smaller right-angled triangles. This approach helps simplify calculations and ensures that you use the correct trigonometric function.

Advanced Trigonometry Word Problems Examples

Advanced problems often involve non-right triangles or three-dimensional geometries. These problems typically require the use of the law of sines or the law of cosines to find unknown measurements.

Law of Sines: \(\frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C}\)

Law of Cosines: \(c^2 = a^2 + b^2 - 2ab \cos C\)

Example: In triangle ABC, you know side a = 8, side b = 6, and angle C = 60 degrees. Find side c.Solution:

  • Using the Law of Cosines, \(c^2 = a^2 + b^2 - 2ab \cos C\)
  • \(c^2 = 8^2 + 6^2 - 2 \cdot 8 \cdot 6 \cdot \cos(60)\)
  • \(c^2 = 64 + 36 - 96 \cdot (1/2) \)
  • \(c^2 = 64 + 36 - 48 \)
  • \(c^2 = 52 \)
  • \(c = \sqrt{52} \)
  • \(c \approx 7.21 \) units

Applications of Trigonometry Word Problems

Trigonometry is not just an abstract mathematical concept; it has numerous practical applications in everyday life, science, and engineering. Understanding how to solve trigonometry word problems can help you navigate through various real-world scenarios effectively.

Everyday Applications of Trigonometry Word Problems

Trigonometry is applied in many everyday activities, whether you realise it or not. Here are a few areas where trigonometric calculations are commonly used:

  • Navigating Maps: You can use trigonometry to calculate distances and angles between various points on a map.
  • Measuring Heights: Determining the height of a tree, building, or any other tall object without climbing it can be done using trigonometric functions.
  • Photography: Calculating the ideal angle and distance to take a picture often involves trigonometry.

Example: You want to measure the height of a flagpole. Standing 20 metres away, you measure the angle of elevation to the top of the pole to be 30 degrees. Find the height of the flagpole.Solution:

  • Using the tangent function: \( \tan(30) = \frac{ h }{ 20 } \)
  • Since \( \tan(30) = \frac{1}{\sqrt{3}} \), then \( \frac{1}{\sqrt{3}} = \frac{ h }{ 20 } \)
  • So, \( h = 20 \cdot \frac{1}{\sqrt{3}} \approx 11.55 \) metres.

Always ensure your units are consistent when solving trigonometric problems involving heights and distances.

Applications of Trigonometry Word Problems in Science

In science, trigonometry plays a crucial role in fields such as physics and astronomy. By understanding trigonometric word problems, scientists can make accurate measurements and predictions. Here are some specific applications:

Law of Sines: \( \frac{ a }{ \sin A } = \frac{ b }{ \sin B } = \frac{ c }{ \sin C } \)

  • Astronomy: Calculating the distance between celestial bodies often involves using the law of sines and the law of cosines.
  • Physics: When studying wave motion or light refraction, trigonometric functions help describe the phenomena accurately.

Example: Astronomers determined the angle between Earth and a distant star is 0.5 degrees, and the distance from Earth to the star is 4 light-years. Find the distance between two observation points on Earth if the angle at the distant star is measured to be 0.001 degrees.Solution:

  • Using the law of sines: \( \frac{ 4 \text{ light-years} }{ \sin 0.001 } = \frac{ d }{ \sin 0.5 } \)
  • Rearrange to solve for \( d \): \( d = \frac{ 4 \cdot \sin 0.5 }{ \sin 0.001 } \)
  • Calculate using the approximate values: \( d \approx 1997.44 \) light-years.

In more complex problems, astronomers and physicists may use spherical trigonometry , which is an extension of trigonometry that deals with spheres rather than planes. This is particularly useful for calculations involving planetary orbits and celestial navigation, where the curvature of space becomes significant.

Applications of Trigonometry Word Problems in Engineering

Engineering makes extensive use of trigonometry, especially in areas such as civil, mechanical and electrical engineering. By applying trigonometric word problems, engineers can design and build structures, machinery, and systems efficiently.

Law of Cosines: \( c^2 = a^2 + b^2 - 2ab \cos C \)

  • Structural Engineering: Calculating the forces in various parts of a structure, such as beams and trusses, often involves trigonometric principles.
  • Mechanical Engineering: Designing gears, engines, and other mechanical components requires knowledge of angles and distances calculated using trigonometry.
  • Electrical Engineering: Analysing AC circuits and waveforms frequently involves trigonometric calculations.

Example: In a truss system, two members join to form a 60-degree angle with each other. If the lengths of the members are 5 metres and 7 metres, find the length of the opposing side.Solution:

  • Using the law of cosines: \( c^2 = 5^2 + 7^2 - 2 \cdot 5 \cdot 7 \cdot \cos 60 \)
  • So, \( c^2 = 25 + 49 - 35 \)
  • \( c^2 = 39 \)
  • \( c = \sqrt{39} \approx 6.24 \) metres.

Understanding the law of cosines is crucial for solving problems involving non-right triangles.

Trigonometric Ratios in Word Problems

Trigonometric ratios are pivotal in solving various mathematical problems. They allow you to find unknown angles or distances in different types of triangles . Applying these ratios in word problems helps you understand their real-world functionality.

Using Sine, Cosine, and Tangent in Word Problems

Sine, cosine, and tangent are the primary trigonometric functions used in solving right triangle problems. They help you relate the angles to the lengths of the sides in a triangle. Here’s a quick refresher on these functions:

Example: You are standing 30 metres away from a tree and the angle of elevation to the top of the tree is 45 degrees. Find the height of the tree.Solution:

  • Using the tangent function: \( \tan(45) = \frac{\text{height}}{30} \)
  • Since \( \tan(45) = 1 \), then \( 1 = \frac{\text{height}}{30} \)
  • So, the height is 30 metres.

Always ensure your calculator is in the correct mode (degrees or radians ) based on the given angle.

Right Triangle Trigonometry Word Problems

Right triangle trigonometry involves solving problems where one angle is 90 degrees. The three main trigonometric ratios — sine, cosine, and tangent — are especially useful in these problems.

  • Identify the right angle: Determine which angle is 90 degrees to simplify your calculations.
  • Choose the appropriate ratio: Decide whether to use sine, cosine, or tangent based on the sides and angles you are dealing with.

Example: A 20-foot ladder is leaning against a wall, making a 60-degree angle with the ground. Find how high up the wall the ladder reaches.Solution:

  • Using the cosine function: \( \cos(60) = \frac{\text{adjacent}}{\text{hypotenuse}} \)
  • \( \cos(60) = \frac{\text{height}}{20} \)
  • Since \( \cos(60) = \frac{1}{2} \), then \( \frac{1}{2} = \frac{\text{height}}{20} \)
  • So, the height is 10 feet.

In more complex problems involving right triangles, it might be helpful to use the Pythagorean theorem in conjunction with trigonometric ratios. The Pythagorean theorem states that for a right triangle, the square of the length of the hypotenuse (\(c\)) is equal to the sum of the squares of the lengths of the other two sides (\(a\) and \(b\)): \( c^2 = a^2 + b^2 \). This theorem can be particularly useful when you have two sides and need to find the third.

Trigonometric Ratios in Non-right Triangle Word Problems

When dealing with non-right triangles, trigonometric ratios can still be utilised, but you may need to employ the law of sines or the law of cosines. These laws help solve for unknown sides or angles.The law of sines states: \[ \frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C} \] While the law of cosines is: \[ c^2 = a^2 + b^2 - 2ab \cos C \]

Example: In triangle ABC, you know that angle A = 30 degrees, angle B = 45 degrees, and side a = 10 units. Find the length of side b.Solution:

  • Using the law of sines: \( \frac{a}{\sin A} = \frac{b}{\sin B} \)
  • So, \( \frac{10}{\sin 30} = \frac{b}{\sin 45} \)
  • Since \( \sin 30 = \frac{1}{2} \) and \( \sin 45 = \frac{\sqrt{2}}{2} \), then \( \frac{10}{0.5} = \frac{b}{0.707} \)
  • \( 20 = \frac{b}{0.707} \)
  • So, \( b = 20 \times 0.707 \approx 14.14 \) units

In non-right triangle problems, always double-check which law applies to the given sides and angles to avoid mistakes.

Practice Solving Trigonometry Word Problems

Practicing trigonometry word problems sharpens your ability to analyse and solve complex mathematical scenarios. Whether you are preparing for exams or simply looking to enhance your understanding, consistent practice can help build your confidence and proficiency.

Tips for Solving Trigonometry Word Problems

Solving trigonometry word problems effectively requires a step-by-step approach. Here are some tips to help you navigate through these problems with ease:

  • Understand the Problem: Carefully read the problem to identify what is being asked and what information is provided.
  • Draw a Diagram: Visual representations can simplify complex problems and highlight relationships between different components.
  • Choose the Correct Function: Depending on the given information, decide whether to use sine, cosine, or tangent.
  • Set Up Equations : Formulate equations using the chosen trigonometric functions and solve for the unknown values.
  • Check Your Work: Always review your calculations and ensure that your answers make sense in the context of the problem.

Example: A building casts a shadow of 15 meters, and the angle of elevation of the sun is 30 degrees. Find the height of the building.Solution:

  • Using the tangent function: \( \tan(30) = \frac{ h }{ 15 } \)
  • Since \( \tan(30) = \frac{1}{\sqrt{3}} \), then \( \frac{1}{\sqrt{3} } = \frac{ h }{ 15 } \)
  • So, \( h = 15 \cdot \frac{1}{\sqrt{3}} \approx 8.66 \) meters.

Always draw a diagram to visualise the problem. This can make it easier to see which trigonometric function to use.

Common Mistakes in Solving Trigonometry Word Problems

When working on trigonometry word problems, certain mistakes are frequently made. Recognising and avoiding these can improve your accuracy:

  • Choosing the Wrong Function: Ensure you clearly understand whether to use sine, cosine, or tangent based on the sides and angles involved.
  • Incorrect Unit Conversion: Make sure all units are consistent, especially when converting between different measurement systems.
  • Ignoring Right-Angle Assumptions : If a problem involves a right triangle, leverage the right-angle properties to simplify calculations.
  • Calculator Mode Errors: Verify that your calculator is set to the appropriate mode (degrees or radians) as required by the problem.
  • Forgetting to Double-Check: Always revisit your steps and calculations to spot any errors.

Keep your work neat and organised. This makes it easier to identify errors and follow your thought process.

Resources for Trigonometry Word Problems Practice

Practicing trigonometry word problems requires access to various resources. Here are some recommended materials to aid your practice:

  • Textbooks: Many mathematics textbooks include sections dedicated to trigonometry and related word problems.
  • Online Tutorials: Platforms like Khan Academy provide instructional videos and practice problems to help you master trigonometry.
  • Practice Worksheets: Printable worksheets that focus on trigonometric word problems can be found on educational websites.
  • Math Apps: Apps like Photomath and WolframAlpha offer tools to solve trigonometric problems step-by-step.
  • Study Groups: Joining a study group can provide additional support and the opportunity to learn different problem-solving techniques.

Trigonometry Word Problems - Key takeaways

  • Trigonometry Word Problems: Utilise trigonometric concepts to solve real-life scenarios, such as measuring heights and navigating maps.
  • Key Trigonometric Functions: Sine (sin), Cosine (cos), and Tangent (tan) are ratios used in right-angled triangles to solve word problems.
  • Steps to Solving Trigonometry Word Problems: Understand the problem, identify the right triangle, choose the correct function, set up the equation, and check your answer.
  • Common Mistakes: Choosing the wrong function, incorrect unit conversion, ignoring right-angle assumptions , calculator mode errors, and not double-checking work.
  • Applications of Trigonometry Word Problems: Used in diverse fields like engineering, physics, navigation, and everyday tasks such as photography and measuring heights.

Flashcards in Trigonometry Word Problems 15

A study of the numerical properties and relationships of complex numbers.

Understand the problem, identify the right triangle, choose the correct function, set up the equation, check your answer.

\text{h} = 10 \times \text{tan}(45) \text{, equal to 10 metres exactly}

Use the secant function: \( sec(60) = \frac{x}{5} \) leading to \( x = 0.5 \) metres.

Use the tangent function: \( tan(45) = \frac{h}{50} \) leading to \( h = 50 \) metres.

Use the Pythagorean theorem with adjustment: \( c^2 = a^2 + b^2 + 2ab \cos C \) leading to \( c = 12 \) units.

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Solving word problems involving triangles and implications on training pre-service mathematics teachers

  • William Guo , 
  • School of Engineering and Technology, Central Queensland University, North Rockhampton, QLD 4702, Australia
  • Academic Editor: Zlatko Jovanoski
  • Received: 18 June 2024 Revised: 02 July 2024 Accepted: 05 July 2024 Published: 09 July 2024
  • Full Text(HTML)
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Triangles and trigonometry are always difficult topics for both mathematics students and teachers. Hence, students' performance in solving mathematical word problems in these topics is not only a reflection of their learning outcomes but also an indication of teaching effectiveness. This case study drew from two examples of solving word problems involving triangles by pre-service mathematics teachers in a foundation mathematics course delivered by the author. The focus of this case study was on reasoning implications of students' performances on the effective training of pre-service mathematics teachers, from which a three-step interactive explicit teaching-learning approach, comprising teacher-led precise and inspiring teaching (or explicit teaching), student-driven engaged learning (or imitative learning), and student-led and teacher-guided problem-solving for real-world problems or projects (or active application), was summarized. Explicit teaching establishes a solid foundation for students to further their understanding of new mathematical concepts and to conceptualize the technical processes associated with these new concepts. Imitative learning helps students build technical abilities and enhance technical efficacy by engaging in learning activities. Once these first two steps have been completed, students should have a decent understanding of new mathematical concepts and technical efficacy to analyze, formulate, and finally solve real-world applications with assistance from teachers whenever required. Specially crafted professional development should also be considered for some in-service mathematics teachers to adopt this three-step interactive teaching-learning process.

  • pre-service mathematics teacher ,
  • word problem ,
  • triangles ,
  • problem-solving ,
  • explicit teaching ,
  • imitated learning ,
  • active applications ,
  • professional development

Citation: William Guo. Solving word problems involving triangles and implications on training pre-service mathematics teachers[J]. STEM Education, 2024, 4(3): 263-281. doi: 10.3934/steme.2024016

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word problems trigonometry with solutions

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  • Figure 1. A sketch of isosceles triangle for the first word problem
  • Figure 2. A reworked sketch for the second problem with derived angles (in red)
  • Figure 3. The first reworked sketch for solving the second problem through right triangles
  • Figure 4. The second reworked sketch for solving the second problem through right triangles
  • Figure 5. The third reworked sketch for solving the second problem through right triangles

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